mathematical question...

[pinkylicious]

There are 7 girls on a bus. Each girl has 7 backpacks and in each backpack there are 7 big cats. For every big cat there are 7 kittens. How many legs are there in the bus? (the driver is not counted)

I actually solved it in 40+ minutes I think...I was using my phone's calculator...:P
I'll scan my solution after someone gets the answer :turned:

[Enigmacsg]

I'm an idiot when it comes to math but I got 70 as an answer. :whistling:

[pimpyourdino]

10,990 i got

[pinkylicious]

sorry, none of you got the right answer...
Pls. try again...:yes:

EDIT://
PIMPYOURDINO GOT THE ANSWER!

[xJennax]

Girls legs: 14

big cats: 343

kittens: 2401

big cats+kittensx4 legs
10976 + 14 girls legs
=10990.

idk if thats right im bad at maths

[jvuonger]

Girls legs: 14

big cats: 343

kittens: 2401

big cats+kittensx4 legs
10976 + 14 girls legs
=10990.

idk if thats right im bad at maths

yeah thats right

(7 girls*2 legs/girl) + (7 girls*7 backpacks/girl* 7 cats/backpack * 4 legs/cat) + (7 girls *7 backpacks/girl *7 cats / backpack * 7 kittens / cat * 4 legs / kitten) = 10990 legs

[geg2]

7 girls x 2 legs = 14 legs from girls

7 girls x 7 backpacks per girl x 7 big cats per backpack x 4 legs per big cat = 1372 legs from big cats

7 girls x 7 backpacks per girl x 7 big cats per backpack x 7 kittens per big cat x 4 legs per kitten = 9604 legs from kittens

Total legs = 14 legs from girls + 1372 legs from big cats + 9604 legs from kittens

Total legs = 10990 legs

[pinkylicious]

xJENNAx AND PIMPYOURDINO GOT THE RIGHT ANSWER!

[xJennax]

edit//nvm i see the first time was right lol.
woooo im so proud lmfao

[jvuonger]

This is fun :online2long:

Here's one:

From a total of 15 people, 3 committees consisting of 3, 4, and 5 people, respectively, are to be chosen. How many sets of committees are possible if no person may serve on more than one committee?

First one to get it in 5 minutes will get $5 paypal from me. lol

Start now! Ends 5:16AM MSP time

[pinkylicious]

you all got the right answer! except for one..

as I've promised:
http://i30.tinypic.com/300f6rs.jpg
---sorry for the language :P

[xJennax]

(5x4x3) x 3
= 180
idk imma try again


(5x4x3) + (4x3x2) + (3x2x1)
= 90

I cant do it, I wish it was an English question lol

[jvuonger]

Answer:

15!/3!*4!*5!*3! = 12,612,600

:winkiss:

[xJennax]

woahhhh ;o
what does the ! represent

[geg2]

factorial

1! = 1
2! = 1x2
3! = 1x2x3
4! = 1x2x3x4
and so forth

[jvuonger]

woahhhh ;o
what does the ! represent

n! means factorial which is the product of all positive numbers less than and equal to n.

So, 5! = 5*4*3*2*1

[Enigmacsg]

I told you I was an idiot in math! :surrender:

[84creations]

I counted 68614 somehow b4 I looked at the answer. :stupid:

[CatHead]

you should've made it a trick question and said how many FEET on the bus, lol

then these guys would've done all that math and you could just say, sorry cats don't have feet, they have paws LOL

[geg2]

Combinations per n objects = Permutations/ n!

A) Combinations from 3 persons = 15 x 14 x 13 / (1 x 2 x 3 )

Now that there are 12 people left after taking away 3,
B) Combinations from 4 persons = 12 x 11 x 10 x 9/ (1 x 2 x 3 x 4)

Now that there are 8 people left after taking away 4,
C) Combinations from 5 persons = 8 x 7 x 6 x 5 x 4/ (1 x 2 x 3 x 4 x 5)

Possible combinations = A) x B) x C)

= 15 x 14 x 13 x 12 x 11 x 10 x 9 x 8 x 7 x 6 x 5 x4 / (3! x 4! x 5! ) = 15! / (3! x 4! x 5! x 3!)

[pinkylicious]

you should've made it a trick question and said how many FEET on the bus, lol

then these guys would've done all that math and you could just say, sorry cats don't have feet, they have paws LOL

haha LOL!...

[pinkylicious]

Combinations per n objects = Permutations/ n!

A) Combinations from 3 persons = 15 x 14 x 13 / (1 x 2 x 3 )

Now that there are 12 people left after taking away 3,
B) Combinations from 4 persons = 12 x 11 x 10 x 9/ (1 x 2 x 3 x 4)

Now that there are 8 people left after taking away 4,
C) Combinations from 5 persons = 8 x 7 x 6 x 5 x 4/ (1 x 2 x 3 x 4 x 5)

Possible combinations = A) x B) x C)

= 15 x 14 x 13 x 12 x 11 x 10 x 9 x 8 x 7 x 6 x 5 x4 / (3! x 4! x 5! ) = 15! / (3! x 4! x 5! x 3!)

I can't understand any of that...I'm still a freshmen

[xJennax]

I've never heard of the ! being factorial, never even seen it...either has my bf and he's doing advanced maths. :S

Geg, I crown you Maths King.

[stephysan]

i dont even understand the first one..... lmfaoo
im SLOW when it comes to stuff like this :(

[jvuonger]

I've never heard of the ! being factorial, never even seen it...either has my bf and he's doing advanced maths. :S

Geg, I crown you Maths King.

I remember it being taught in Trigonometry class for some odd reason. Not sure if you have had it or not. Otherwise, it's revisited in Probability/Statistics, Discrete Mathematics, and a couple others.